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The depth of the water at the end of a pier changes periodically along with the movement of tides. on a particular day, low tides occur at 12:00 a.m. and 3:30 p.m., with a depth of 3.25 meters, while high tides occur at 7:45 a.m. and 11:15 p.m., with a depth of 8.75 meters. which of the following equations models d, the depth of the water in meters, as a function of time, t, in hours? let t = 0 be 12:00 a.m. d = negative 3.75 cosine (startfraction 4 pi over 31 endfraction t) 5 d = negative 3.75 cosine (startfraction 4 pi over 29 endfraction t) 5 d = negative 2.75 cosine (startfraction 4 pi over 31 endfraction t) 6 d = negative 2.75 cosine (startfraction 4 pi over 29 endfraction t) 6

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shubhamchouhanvrVT

In this exercise we have to calculate the value of the water depth, so we have: d=5.5Cos(12t)+6

What are periodic waves?

A periodic wave is a wave with a repeating continuous pattern that determines its wavelength and frequency

Putting together some information given in the statement we have:

  • The minimum depth of 3.25 m occurs at 12:00 am and at 3:30 pm.
  • Therefore the period t=0 will be  12:00 am.
  • The maximum depth of 8.75 m occurs at 7:45 am and at 11:15 pm.

Knowing that the formula will be given by an equation similar to:

[tex]d=acos(bt)+k[/tex]

Where:

  • d = depth, m
  • t = time, hours
  • a= amplitude

The amplitude difference is given by:

[tex]8.75-3.25=5.5\ m[/tex]

The mean depth is:

[tex]k=\dfrac{(3.25+8.75)}{2}=6\ m[/tex]

Then writing the equation with;

[tex]d=acos(bt)+k\\\\d=5.5cos(12t)+6[/tex]

Hence the value of water depth will be d=5.5Cos(12t)+6

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