The dimensions of a rectangle with an area of 40 square units and the length is 6 more than the width is 10 by 4.
area of a rectangle = lw
where
Therefore,
area = 40 square units
The length is 6 unit greater than the width. Hence,
l = 6 + w
Therefore,
40 = w(6 + w)
40 = 6w + w²
w² + 6w - 40 = 0
w² - 4w + 10w - 40 = 0
w(w - 4) + 10(w - 4) = 0
(w + 10)(w - 4) = 0
w = - 10 or 4
We can only use the positive number.
Hence,
w = 4 units
l = 6 + 4 = 10 units
The dimension are 10 by 4.
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