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Find the magnitude of the force needed to accelerate a 220 g mass with a⃗ = -0.205 m/s2 i^+0.400 m/s2 j^.

Respuesta :

David1993
As , Fr = m.a

With mass in kg

We have:

m = 220g

m = 0,22kg

We have too:

a = -0,205m/s^2 i + 0,400m/s^2 j

Remembering that "a" is in vector

a = axi + ayj

a = √( ax^2 + ay^2)

a = √( (-0,205)^2+(0,400)^2 )

a = √( 0,202025)

a ~ 0,449 m/s^2

Then,

Fr = m.a

Fr = 0,22 . 0,449

Fr ~ 0,09888 N

Fr ~ 9,88 . 10^(-2) N

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