Respuesta :

[tex] \sqrt{15-x}=-3\sqrt{2x+3}\impliedby \textit{divide by -3} \\ \quad \\ \cfrac{\sqrt{15-x}}{-3}=\sqrt{2x+3}\impliedby \textit{squares both sides} \\ \quad \\ \left( \cfrac{\sqrt{15-x}}{-3} \right)^2=(\sqrt{2x+3})^2\implies \cfrac{(\sqrt{15-x})^2}{(-3)^2}=(\sqrt{2x+3})^2 \\ \quad \\ \cfrac{15-x}{9}=2x+3\impliedby \textit{multiply both sides by 9} \\ \quad \\ 15-x=18x+27\impliedby \textit{solve for "x"}[/tex]

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