If f(1) = 0, what are all the roots of the function f (x) = x cubed + 3 x squared minus x minus 3? Use the Remainder Theorem.
x = –1, x = 1, or x = 3
x = –3, x = –1, or x = 1
x = –3 or x = 1
x = –1 or x = 3

Respuesta :

Answer:

x = –3, x = –1, or x = 1

Step-by-step explanation:

when I put -3.-1,or 1 as x I get 0

Remainder Theorem Way :

x^3-3x^2-x-3

x^2 (x+3) -1(x+3) = 0

(x^2 -1) (x+3) = 0

(x+1) (x-1) (x+3) = 0

x= 1 x= -1 x= -3

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Answer:

b

Step-by-step explanation: