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Marcel walks due north 50 meters from a tree. Katya walks 20 meters in a straight line away from the same tree but at an angle of 42° from due north, as shown in the diagram below. How far apart are Marcel and Katya to the nearest meter?

Marcel walks due north 50 meters from a tree Katya walks 20 meters in a straight line away from the same tree but at an angle of 42 from due north as shown in t class=

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abidemiokin

The distance from Marcel and Katya is 34 metres

SOH CAH TOA identity

From the given diagram, we have the following

  • Hypotenuse = 50m
  • Opposite = x

Acute angle given = 42 degrees

According to SOH CAH TOA identity

sin theta = opp/hyp

sin 42 = x/50

x = 50sin42

x = 50(0.6691)

x = 33.46

Hene the distance from Marcel and Katya is 34 metres

Learn more on SOH CAH TOA here: https://brainly.com/question/20734777

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