A 12.1 M HCl solution with a density of 1.19 g/mL has a molality of 16.1 m.
What is molality?
Molality is defined as the total moles of a solute contained in a kilogram of a solvent.
Let's suppose we have 1 L of the solution.
- Step 1: Calculate the moles and mass of HCl (solute) in 1 L of solution.
The solution is 12.1 M, that is, there are 12.1 moles of HCl in 1 L of solution.
The molar mass of HCl is 36.465 g/mol.
12.1 mol × 36.465 g/mol = 441 g
- Step 2: Calculate the mass corresponding to 1 L of solution.
The density of the solution is 1.19 g/mL.
1000 mL × 1.19 g/mL = 1190 g
- Step 3: Calculate the mass of water (solvent) in 1190 g of solution.
In 1190 g of solution, there are 441 g of HCl.
mWater = 1190 g - 441 g = 749 g = 0.749 kg
- Step 4: Calculate the molality (b) of the solution.
b = 12.1 mol / 0.749 kg = 16.1 m
A 12.1 M HCl solution with a density of 1.19 g/mL has a molality of 16.1 m.
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