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22-12-2021
Physics

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What capacitance is needed to store 3μC of charge at a voltage of 120V?

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mdiary602 mdiary602

24-12-2021

Answer:

C = 0.025F

Explanation:

Charge =q=3×[tex]10^{-6}[/tex]C

Voltage=V=120V

Q=CV

C=Q/V

=3×[tex]10^{-6}[/tex]/120

=1/40×[tex]10^{-6}[/tex]

C = 0.025F

C=2.5 [tex]10^{-4}[/tex]C 0r 25 ×[tex]10^{-3}[/tex]F

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