Respuesta :
The completed proof is presented as follows;
By definition of a rhombus [tex]\overline{JK} \cong \overline{KM}[/tex] and by the reflexive property of
congruence [tex]\overline{KP} \cong \overline{KP}[/tex], because the diagonals of a rhombus bisect a pair
of opposite angles, ∠JKP ≅ ∠MKP, making ΔJKP ≅ ΔMKP by the SAS
congruency postulate, because CPCTC, ∠JPK ≅ ∠MPK, and these angles
are right angles because two angles that form a linear pair are congruent,
thereby making, [tex]\overline{JK} \perp \overline{KM}[/tex] by definition of perpendicular segments.
Reasons:
Please find attached the drawing of the given rhombus JKMH, that show
the point of intersection of the diagonals JM and HK at point P.
- A rhombus is an equilateral quadrilateral, therefore, the adjacent sides [tex]\overline{JK} \ and \ \overline{KM}[/tex] are congruent.
- The SAS congruency postulate states that if a triangle has two sides and an included angle that are congruent to two sides and an included angle of another triangle, then the two triangles are congruent.
- CPCTC is an acronym for Congruent Parts of Congruent Triangles are Congruent.
Learn more about the properties of a rhombus here:
https://brainly.com/question/10618409
