Answer:
[tex](0;-4) (3,0); (6,4); (9,8)[/tex]
Step-by-step explanation:
You will end up with ordered pairs. the way to find them is to assign convenient values to either x OR y, and find the remaining ones. by "convenient" i would recommend having either equal to zero, and then playing with coefficients so that something else goes to "convenient" numbers - since I'm lazy and I hate typing fractions in here.
[tex]x= 0 \rightarrow 4(0) -3y=12 \rightarrow y=-4;\\y=0 \rightarrow 4x -3(0) = 12 \rightarrow x=3;\\x=6 \rightarrow 4(6)-3y=12 \rightarrow -3y=-12 \rightarrow y=4\\y= 8 \rightarrow 4x-(3)(8)=12\rightarrow 4x=36 \rightarrow x=9[/tex]
How did I choose 6 and 8? Mostly practice and a bit of good eye. 12 at the RHS is 4 times 3, and the LHS is 4 times something, minus 3 times something else, so it was a good bet that picking multiples of the other something would cancel out.
