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How many moles of N₂ are essential for generating 0.08 moles of Li₃N in the given reaction?
6Li + N₂ 2Li₃N

0.013 moles

0.04 moles

0.08 moles

0.16 moles

0.48 moles

Respuesta :

diene
For every 2 moles of Li3N, you need 1 mole of N2
so for 0.08 mol Li3N, you need 0.04 moles N2
So 0.04moles of N2 is required.
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