Answer:
[tex]{ \tt{ {4x}^{6} - {16x}^{2} = {(2x {}^{3}) }^{2} - {(4x)}^{2} }} \\ [/tex]
• from difference of squares:
[tex]{ \boxed{ \rm{( {a}^{2} - {b}^{2} ) = (a - b)(a + b)}}}[/tex]
• a → 2x³
• b → 4x
[tex]{ \underline{ \underline{ \tt{ = \: (2 {x}^{3} - 4x)(2 {x}^{3} + 4x) \: }}}}[/tex]
