Answer:
A and D
Step-by-step explanation:
x^2+2x-6=0 is a quadratic equation, the roots of this equation is given by the formula: [tex]x=(-b+-(\sqrt{b^2-4ac} ))/2a[/tex] (where z=1, b=2, c=-6), so[tex]x=(-b+-(\sqrt{b^2-4ac} ))/2a=(-2+-(\sqrt{2^2-4*1*-6} ))/2*1=-1+-\sqrt{7}[/tex]
which are answers A and D.
