Answer:
The magnitude of the friction force is 8197.60 N
Explanation:
Using the definition of the centripetal force we have:
[tex]\Sigma F=ma_{c}=m\frac{v^{2}}{R}[/tex]
Where:
- m is the mass of the car
- v is the speed
- R is the radius of the curvature
Now, the force acting in the motion is just the friction force, so we have:
[tex]F_{f}=m\frac{v^{2}}{R}[/tex]
[tex]F_{f}=2100\frac{18^{2}}{83}[/tex]
[tex]F_{f}=8197.60 \: N[/tex]
Therefore the magnitude of the friction force is 8197.60 N
I hope it helps you!
