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A pitcher claims he can throw a 0.174 kg baseball with as much momentum as a speeding bullet. Assume that a 5 g bullet moves at a speed of 1,115 m/s. What must the baseball’s speed (m/s) be if the pitcher’s claim is valid?

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Corsaquix

Answer:

[tex]320.4\:\mathrm{m/s}[/tex]

Explanation:

The momentum of an object is given by [tex]p=mv[/tex]. Therefore, we have the following equation:

[tex]m_{ba}v_{ba}=m_{bu}v_{bu},\\0.174\cdot v_{ba}=0.005\cdot 1115,\\v_{ba}\approx \boxed{320.4\:\mathrm{m/s}}[/tex]

*Note: it's important to convert grams to kilograms, as kilograms are the SI unit for mass

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