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Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 70 cm.

Required:
a. What is the wavelength of the sound?
b. If the distance between the speakers continues to increase, at what separation will the sound intensity again be a maximum?

Respuesta :

Manetho

Answer:

Explanation:

The path length difference = extra distance traveled

The destructive interference condition is:

[tex]\Delta d = (m+1/2)\lambda[/tex]

where m =0,1, 2,3........

So, ←

[tex]\Delta d = (m+1/2)\lamb da9/tex]

so [tex]\Delta d = \frac{\lambda}{2}[/tex]

⇒ λ = 2Δd = 2×10 = 20

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