Respuesta :

Answer:

Ka = 1.14x10⁻⁸

Explanation:

First we calculate [H⁺] from the pH:

  • pH = -log[H⁺]
  • [H⁺] = [tex]10^{-pH}[/tex]
  • [H⁺] = 6.31x10⁻⁵ M

For a monoprotic weak acid, the molar concentration of H⁺ of a solution can be expressed as:

  • [H⁺] = √(C*Ka)

Where C is the molar concentration of the weak acid solution.

  • 6.31x10⁻⁵ M = [tex]\sqrt{0.35M*Ka}[/tex]
  • 1.14x10⁻⁸ = Ka