Answer:
let x1=2, y1 = -6 ,x2 = -1, y2 = 6
first we find gradient of the line
gradient = (y2-y1) / (x2 -x1)
(6-(-6))/(-1-2)
(6+6)/(-3)
12/-3
-4
equation is;
M=( y-y1)/(x-x1)
whereM is a gradient
we substitute
-4=(y-(-6))/(x-2(
-4=(y+6)/(x-2)
by cross multiplication
-4(x-2)=(y+6)
-4x+8=y+6
-4x+8-6-y=0
-4x-y+2=0
