Answer:
[tex]C=2.45\frac{J}{g\°C}[/tex]
Explanation:
Hello there!
In this case, since the thermodynamic definition of heat in terms of mass, specific heat and temperatures is given by:
[tex]Q=mC(T_2-T_1)[/tex]
We are to calculate the specific heat of the ethanol as shown below:
[tex]C=\frac{Q}{m(T_2-T_1)}[/tex]
Thus, by plugging it the given data we can obtain:
[tex]C=\frac{4650J}{250.0g(29.6-22.00\°C)} \\\\C=2.45\frac{J}{g\°C}[/tex]
Regards!
