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Question 19 (2 points)
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How many milliliters of a 0.200 M NaOH solution are needed to react with 28.0 mL
of a 0.500 M NiCl2 solution?
NiCl2 (aq) + 2NaOH (aq)
Ni(OH)2 (s) + 2NaCl (aq)
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Respuesta :

Answer:

Explanation: NiCl2 (aq) + 2NaOH (aq)

                      Ni(OH)2 (s) + 2NaCl (aq)

M(NiCl2)= 0.500 M

M(NaOH)=0.200 M

V(NiCl2)= 28.0 mL

According to balanced reaction:

2*number of mol of NiCl2 =1*number of mol of NaOH

2*M(NiCl2)*V(NiCl2) =1*M(NaOH)*V(NaOH)

2* 0.50 M * 28.0 mL = 1* 0.2 M* V(NaOH)

V (NaOH) =  140 mL

Answer : 140 mL

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