Respuesta :

Answer:

[tex] \sqrt{125 } \\ = 11.18[/tex]

It is in between 0 to 12.

Answer:

√125 must be between 11 and 12.

Step-by-step explanation:

Identify perfect squares in the neighborhood of 125:  

121 = 11^2      or      √121 = 11

144 = 12^2               √144 = 12

√125 must therefore be between 11 and 12.