contestada

an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per second. The radius of the hammer's path is 2.0 meters.

Respuesta :

hamzaahmeds

Answer:

ac = 72 m/s²

Fc = 504 N

Explanation:

We can find the centripetal acceleration of the hammer by using the following formula:

[tex]a_c = \frac{v^2}{r}[/tex]

where,

ac = centripetal acceleration = ?

v = constant speed = 12 m/s

r = radius = 2 m

Therefore,

[tex]a_c = \frac{(12\ m/s)^2}{2\ m}[/tex]

ac = 72 m/s²

Now, the centripetal force applied by the athlete on the hammer will be:

[tex]F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)[/tex]

Fc = 504 N