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A thin 2.09 m long copper rod in a uniform
magnetic field has a mass of 40.6 g. When
the rod carries a current of 0.229 A directed
perpendicular to the magnetic field, it floats
in the magnetic field.
The acceleration of gravity is 9.81 m/s²
.
What is the field strength of the magnetic
field?
Answer in units of T ...?

Respuesta :

The solution to the problem is as follows:
ILB = mg 

B = mg / (IL) = (.0406)(9.81) / ( (.229)(2.09) ) = 0.8322 Tesla

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