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In ΔMNO, the measure of ∠O=90°, the measure of ∠M=64°, and NO = 70 feet. Find the length of MN to the nearest tenth of a foot.
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In ΔMNO the measure of O90 the measure of M64 and NO 70 feet Find the length of MN to the nearest tenth of a foot Will give brainliest class=

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Answer:

in triangle MNO

relationship between perpendicular and hypotenuse is given by sin angle

sin64°=p/h=70/x

x=70/sin64°=77.88foot

length of MN to the nearest tenth of a foot.

=78ft

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