Find the sum of the first 33 terms of the following series, to the nearest
integer.
2,8, 14, ...

Answer:
3234
Step-by-step explanation:
The series is arithmetic with a common difference = d = 6
First we need to find the 33rd term. Use the formula [tex]a_{n} = a_{1} + (n - 1)d[/tex] where n = 33 and [tex]a_{1} = 2[/tex]
[tex]a_{33} = 2 + (33 - 1)6 = 2 + 32(6) = 194[/tex]
Now the formula for the sum of an arithmetic series is [tex]S_{n} = \frac{n(a_{1} + a_{n} )}{2}[/tex]
So, [tex]S_{33} = \frac{33(2 + 194)}{2}[/tex]
= [tex]\frac{33(196)}{2}[/tex]
= 3234