Triangle TVW is dilated according to the rule
DO,(x,y)(three-fourths x, three-fourths y) to create the image triangle T'V'W', which is not shown.

On a coordinate plane, triangle T V W has points (negative 4, 8), (0, 4), and (4, 4).

What are the coordinates of the endpoints of the segment T'V'?

T'(-3, 6) and V'(0, 3)
T'(-3, 6) and V'(0, 1)
T'(-1, 2) and V'(0, 3)
T'(-1, 2) and V'(0, 1)

Dilation of triangle means each point is stretched outwards or inwards from the center point by multiplying by the scale factor to form a similar triangle.

We have,

Triangle [tex]T V W[/tex] which has points [tex](- 4, 8)[/tex], [tex](0, 4)[/tex], and [tex](4, 4)[/tex] on a coordinate plane.

Scale factor [tex]\frac{3}{4} x, \ \frac{3}{4} y[/tex]

It has to be dilated to create a new triangle [tex]T'V'W'[/tex] .

So,

To create a new triangle [tex]T'V'W'[/tex] we have to multiply the original triangle's coordinate by scale factor, to get new triangle's coordinate .

So, we have to dilate the coordinates by [tex]\frac{3}{4} x, \ \frac{3}{4} y[/tex] ,

[tex]T'=(- 4, 8)=\frac{3}{4} *(-)4, \frac{3}{4} *8= (-3,6)[/tex]

[tex]V'=(0, 4)=\frac{3}{4} *0, \frac{3}{4} *4=(0,1)[/tex]

[tex]W'=(4, 4)=\frac{3}{4} *4,\frac{3}{4} *4=(0,0)[/tex]

So, the coordinates of triangle [tex]T'V'W'[/tex] after dilation are [tex](-3,6), \ (0,1), \ (0,0)[/tex] . Hence we can say that the coordinates of the endpoints of the segment [tex]T'V'[/tex] are [tex](-3,6), \ (0,1).[/tex]

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