Answer:
[tex]y=\dfrac{3}{4}x+15[/tex]
Step-by-step explanation:
Given that,
A line goes through the point (-8,9), and has a slope of 3/4.
We need to express in the form of Ax+B for this line.
We have, m = 3/4
So,
[tex]y=\dfrac{3}{4}x+B[/tex]
Put y = 9 and x = -8 in the above equation.
[tex]9=\dfrac{3}{4}(-8)+B\\\\9=-6+B\\\\9+6=B\\\\B=15[/tex]
So,
[tex]y=\dfrac{3}{4}x+15[/tex]
It is the required equation of the line.
