The pen for Ruth’s dog is 7 feet long and 612 feet wide. Her friend Ralph’s dog pen is 14 feet long and 612 feet wide. How many times larger is the area of Ralph’s dog pen?

Respuesta :

Using the area of a rectangle, it is found that the area of Ralph’s dog pen is 2 times larger.

What is the area of a rectangle?

The area of a rectangle of length l and width w is given by:

[tex]A = lw[/tex]

The pen for Ruth’s dog is 7 feet long and 612 feet wide, hence the area in square inches is given by:

[tex]A_{Ru} = 7 \times 612 = 4284[/tex]

For Ralph's, we have that it is 14 feet long and 612 feet wide, hence:

[tex]A_{Ra} = 14 \times 612 = 8568[/tex]

The ratio is:

[tex]r = \frac{A_{Ra}}{A_{Ru}} = \frac{8568}{4284} = 2[/tex]

The area of Ralph’s dog pen is 2 times larger.

More can be learned about the area of a rectangle at https://brainly.com/question/10489198