Answer:
600
Explanation:
Requirement "What sample size is required if the Office of Student Affairs has no knowledge of the approximate value of p? (Round your answer up to the next largest integer)."
Margin of error, m = 0.04
Confidence level, 1-∝=0.95
Assume that p = 0.5 as proportion is not given.
At 95% confidence(∝=0.05). the tabulated value from the z-table is 1.96
n = p(1-p)[z∝/m]^2
n = (0.5)(1-0.5)[1.96/0.04]^2
n = (0.5)(0.5)(2401)
n = 600.25
n = 600
So, the required samplesize would be 600
