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A dish washer manufacturer introduced a new type of dish washer and conducted a survey on the new product. The survey showed 40% of the consumers had seen an advertisement for the new product, 20% had tried the new product, and 15% had both seen an advertisement and tried the new product. Let event A denote that the consumers had seen an ad for the new product, and event B denote that the consumers had tried the new product. What is the probability a randomly selected consumer had either seen an advertisement or tried the new product

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okpalawalter8

Answer:

[tex]P(A \cup B) =0.45[/tex]

Step-by-step explanation:

From the question we are told that

Consumers seen the soap [tex]P_A=40\% =0.40[/tex]

Consumers used the soap [tex]P_B=20\% =0.2[/tex]

Consumers seen/tried the soap [tex]P_x=15\% =0.15[/tex]

Generally the probability that consumers have seen and tried the soap is

[tex]P(A \cup B=P(A)+P(B)-P(A \cap B[/tex]

[tex]P(A \cup B=0.4+0.2-0.15[/tex]

[tex]P(A \cup B) =0.45[/tex]