Answer:
a) F = 7.20 10⁵ N, b) the force between charges is repulsive.
Explanation:
For this exercise we calculate the electric forces given by Coulomb's law
[tex]F = k \frac{q_{1} q_{2} }{r^{2} }[/tex]
where in this case they indicate that q1 = 5 103 C and q2 = 1 103 C and the distance between them r = 0.25 m
let's calculate
F = [tex]9 10^{9} \ \frac{5 \ 10^{-3} \ \ 1 \ 10^{-3} }{0.25^{2} }[/tex]
F = 7.20 10⁵ N
b) when electric charges have the same sign they repel and when they have the opposite sign they attract.
In this case, charge 1 is negative and charge 2 is negative, therefore, since they both have the same sign, the force between charges is repulsive.
