Answer:
F = 2.25 N
Explanation:
Given that,
Charge 1, [tex]q_1=1\ \mu C = 10^{-6}\ C[/tex]
Charge 2, [tex]q_2=2.5\ \mu C=2.5\times 10^{-6}\ C[/tex]
Distance between charges, d = 10 cm = 0.1 m
We need to find the electric force between charges. The formula that is used to find the electric force is given by
[tex]F=\dfrac{kq_1q_2}{d^2}\\\\F=\dfrac{9\times 10^9\times 10^{-6}\times 2.5\times 10^{-6}}{(0.1)^2}\\\\=2.25\ N[/tex]
Hence, the force between charges is 2.25 N.
