Answer:
The answer is "12".
Step-by-step explanation:
The AP value is:
[tex]\to 16 + 32 = 48;\\\\ \to 80.. an = 32 \\\\\to n = 16\\\\[/tex]
try with [tex]11 = 32 (12) = 368[/tex]
by adding the terms an [tex]= \frac{n}{2} \ \ \ \ (an. A_1)[/tex]
[tex]\to S_{12} = \frac{12}{2} \ (16 + 368) \\\\\\[/tex]
[tex]=6(384)\\\\=2304[/tex]
So, the correct answer is = 12.
