A golf ball is hit on the moon so that
the height of the ball (in feet) is modeled by the
function h(x)=-2.7t^2+21.6t after t seconds.
The ball will land in t = ? seconds

I am just not sure if I did this properly. My professor hasn't really gone over when to use the range equation but I would assume range would equal the distance traveled therefore can be used for this problem. If not the how would I go about solving this? I did 1/6*9.8=1.63 for g on the moon Then used R=(Vi^2sin2theta)/g so on the moon R=((28^2)sin2*35)/1.63=452m

Please Brainliest..? thx

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A golf ball is hit on the moon so that the height of the ball (in feet) is modeled by the function h(x)=-2.7t^2+21.6t after t seconds. The ball will land in t = ? seconds

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A golf ball is hit on the moon so that
the height of the ball (in feet) is modeled by the
function h(x)=-2.7t^2+21.6t after t seconds.
The ball will land in t = ? seconds