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Given that f(x)= [tex]\frac{x^{2}-3 }{2}[/tex]
A) Find [tex]f^{-1}(x)[/tex]
B) Find [tex]f^{-1} (11)[/tex]
Separate your 2 answers for part B with a comma.
I've solved [tex]f^{-1}(x)[/tex], which was [tex]\sqrt{2x+3}[/tex]

However after this I do not see how I can get another value other than 5.

Respuesta :

Answer:

[tex]x=5,-5[/tex]

Step-by-step explanation:

[tex]\\ y=\frac{x^2-3}{2}\\\\ x=\frac{y^2-3}{2}\\\\ 2x=y^2-3\\\\ y^2=2x+3\\\\ f^{-1}(x)=\pm\sqrt{2x+3}\\\\ f^{-1}(x)=\pm\sqrt{2(11)+3}\\=\pm\sqrt{25}=\pm 5[/tex]

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