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I shoot a pumpkin out of a cannon at the national punkin’- chunkin’ competition at a 35º angle at 1440 km/h (400.m/s).

How high does it go?
How far away does it >SPLAT< ?

Respuesta :

abidemiokin

Answer:

Explanation:

How high is the maximum height.

Maximum Height = u²sin²Ф/2g

Given

u = 400m/s

Ф = 35°

H = 400²(sin35)²/2(9.81)

H =  160,000*0.3289/19.62

H = 52638.39/19.62

H = 2682.89m

Hence the cannon went 2682.89m high

b) How far is the range:

R = U²sin2(Ф)/g

R = 400²sin70/9.81

R = 160000*0.9397/9.81

R = 150350.8/9.81

R = 15,326.28m

This means that the cannon went 15,326.28 m far