The members of set A are the integer solutions of the inequality 2x−5≤11 and the members of set B are the integer solutions of the inequality −2x+7≤−9. What is one member of the intersection of A and B?

Respuesta :

Answer:

8

Step-by-step explanation:

[tex]2x-5\leq 11\\2x\leq 16\\x\leq 8[/tex]

[tex]-2x+7\leq -9\\-2x\leq -16\\x\geq 8[/tex]

Once [tex]x \in \mathbb{Z}[/tex] we can conclude that

[tex]A=(-\infty, 8][/tex]

[tex]B=[8, \infty)[/tex]

So [tex]A\cap B = 8[/tex]