Answer:
Area of the polygon = 46 square units
Step-by-step explanation:
Irregular polygon is in a composite figure having triangle A, rectangle B and rectangle C.
Area of the polygon = Area of triangle A + Area of rectangle B + area of rectangle C
Area of triangle A = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]
= [tex]\frac{1}{2}(8)(2)[/tex]
= 8 square units
Area of rectangle B = Length × Width
= 8 × 4
= 32 square units
Area of rectangle C = 3 × 2
= 6 square units
Area of the polygon = 8 + 32 + 6
= 46 square units
