Find the sample variance and standard deviation. ​, ​, ​, ​, ​, ​, ​, ​, ​, Choose the correct answer below. Fill in the answer box to complete your choice. ​(Round to two decimal places as​ needed.)

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This question is incomplete, the complete question is;

Find the sample variance and standard deviation.

7​, 55​, 14​, 49​, 32​, 23​, 30​, 32​, 34​,27

Choose the correct answer below. Fill in the answer box to complete your choice. ​(Round to two decimal places as​ needed.)

Answer:

Sample Variance S² = 205.79

Sample standard deviation S = 14.35

Step-by-step explanation:

Given that;

the observation are;  7​, 55​, 14​, 49​, 32​, 23​, 30​, 32​, 34​,27

First we calculate Sample Mean

⁻x = (∑xi) / n

⁻x = ( 7​ + 55​ + 14​ + 49​ + 32​ +  23​ + 30​ + 32​ + 34​ + 27 ) / 10

⁻x  = 303 / 10 = 30.3

mean ⁻x  = 30.3

now to calculate Sample  variance;

Sample Variance S² = (∑(xi  - ⁻x )²) / (n-1)

⁻x is sample mean

xi is element in the sample

n is sample size

so

Xi                (xi  - ⁻x )                (xi  - ⁻x )²

7​                   -23.3                   542.89

55​                 24.7                    610.09

14​                 -16.3                    265.69

49​                 18.7                    349.69

32​                  1.7                     2.89

23​                -7.3                     53.29

30​                -0.3                     0.09

32​                  1.7                     2.89

34​                 3.7                     13.69

27                -3.3                     10.89

TOTAL ∑                               1852.1  

Sample Variance S² = (∑(xi  - ⁻x )²) / (n-1)

So we substitute

Sample Variance S² =   1852.1  / ( 10 - 1)

Sample Variance S² =  1852.1  / 9

Sample Variance S² = 205.79

Sample standard deviation S = √ [ (∑(xi  - ⁻x )²) / (n-1)]

i.e Sample standard deviation S = √ ( Sample Variance )

Sample standard deviation S = √ 205.79

Sample standard deviation S = 14.35