Answer:
The brick was traveling at 49 m/s the instant before hitting the ground.
Explanation:
When an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The final velocity of a free-falling object after a time t is given by:
[tex]vf=g.t[/tex]
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
The brick takes 5 seconds to land from the high scaffold. The speed at which it lands is:
[tex]vf=9.8\cdot 5[/tex]
vf=49 m/s
The brick was traveling at 49 m/s the instant before hitting the ground.
