djnederlander
djnederlander
21-09-2016
Mathematics
contestada
What is the inverse of f(x)=x^-9
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nobillionaireNobley
nobillionaireNobley
25-09-2016
[tex]y = \frac{1}{x^9}\\yx^9 = 1\\x^9 = \frac{1}{y}\\x = \sqrt[9]{\frac{1}{y}}\\Therefore, \ f^{-1}(x)=\sqrt[9]{\frac{1}{x}}.[/tex]
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