A projectile is launched upward from a height of 704 feet with an initial velocity of 112 ft/s. The equation gives the height h after t seconds. find the number of seconds until it returns to the ground
We are given the data ho equal to 704 feet and vo equal to 112 feet per second. We apply then kinematics equation: h = ho + vot - 1/2 gt2. Substituting to the given equation, h = 704 + 112t - 1/2 * 32*t2when h is equal to zero,0 = 704 + 112t - 1/2 * 32*t2t is equal to 11 seconds
