How long would it take Jesse with an acceleration of -2.50 m/s^2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?
a.6.1 s
b.3.7 s
c.12.1 s
D.5.4 s

Respuesta :

Answer:

use first equation of motion v=u+at..v is 0..since we have to take him to rest and u is 13.5

Explanation:

u = 13.5 m/s

a = - 2.5 m/s^2

v = u + at

0 = 13.5 - 2.5 * t

t (time to reach a complete halt) = 5.4 sec