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A cat walks at a leisurely pace of 2 m/s. It spots a mouse and starts to sprint, chasing the mouse down the street. It takes the cat 3 s to reach a top speed of 20 m/s. Calculate the cat's rate of acceleration during this time.

Respuesta :

Answer:

[tex]a=6\ m/s^2[/tex]

Explanation:

Initial speed of a cat, u = 2m/s

It takes the cat 3 s to reach a top speed of 20 m/s.

We need to find the cat's rate of acceleration during this time. Acceleration is equal to the rate of change of velocity. So,

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{20-2}{3}\\\\a=6\ m/s^2[/tex]

So, the acceleration of the cat is [tex]6\ m/s^2[/tex].

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