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Find the value of k for which the point (1, -2) lies on the graph of the
linear equation x - 2y + k = 0.

Please answer with steps!
No wrong/spam answers!

Respuesta :

r03e

Answer:

k= -5

Step-by-step explanation:

When x=1 and y= -2,

x-2y+k=0

1 -2(-2)+ k=0

1+4+k=0

5+k=0

k= -5

Hrishii

Answer:

k = - 5

Step-by-step explanation:

Since point (1, - 2) lie on the line x - 2y + k = 0.

So, plug x = 1 & y = - 2 in the given equation of line, we find:

[tex]1 - 2( - 2) + k = 0 \\ 1 + 4 + k = 0 \\ 5 + k = 0 \\ \implies \huge \purple{ \boxed{\: k = - 5}}[/tex]

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