One factor of the polynomial 6x3 − x2 + 8x + 5 is (2x + 1). What is the other factor of the polynomial? (Note: Use long division.)

Respuesta :

Answer:

(3x^2 - 2x + 5)

Step-by-step explanation:

3x^2 - 2x + 5

[tex]2x + 1 \sqrt{6 {x}^{3} - {x}^{2} + 8x + 5 } [/tex]

- (6x^3 + 3x^2)

-4x^2 +8x +5

- (-4x^2 - 2x)

10x + 5

-(10x + 5)

00

(2x+1) (3x^2 - 2x + 5) = 6x^3 - x^2 + 8x + 5

Therefore the other factor of the polynomial is (3x^2 - 2x + 5)

Answer: (3x2 − 2x + 5)

Step-by-step explanation: