Answer:
0.651%
Step-by-step explanation:
using Binomial expansion: nCr*p^n*(1-p)^(n-r)
probability he will get at least 5 hits in the game = probability he will get 5 hits in the game + probability he will get 6 hits in the game + probability he will get 7 hits in the game = 7C5*0.215^5*(1-0.215)^2 + 7C6*0.215^6*(1-0.215)^1 +7C7*0.215^7*(1-0.215)^0 = 21* 0.0004594*0.616225 + 7*0.00009877*0.785 + 1*0.000021235 = 0.00651 = 0.651%
