Respuesta :

Answer:

see explanation

Step-by-step explanation:

Given

[tex]\frac{\frac{1}{x} }{(\frac{1}{x})^2+1 }[/tex]

= [tex]\frac{\frac{1}{x} }{\frac{1}{x^2}+1 }[/tex]

Multiply numerator/ denominator by x² to clear the fractions

= [tex]\frac{\frac{1}{x}(x^2) }{(\frac{1}{x^2}+1)x^2 }[/tex]

= [tex]\frac{x}{1+x^2}[/tex]

= [tex]\frac{x}{x^2+1}[/tex]