Answer:
17.32 minutes
Step-by-step explanation:
The standard deviation for a uniform distribution is:
[tex]\sigma =\frac{b-a}{\sqrt12}[/tex]
If a = 20 minutes and b = 80 minutes, the standard deviation is:
[tex]\sigma =\frac{80-20}{\sqrt12} \\\sigma=17.32\ minutes[/tex]
The standard deviation of the distribution of consumer usage time of computers in the public library is 17.32 minutes.
