rashyasullivan1
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A 10 N block is at the bottom of a frictionless incline as shown to the right. How much work must be done against gravity to move it to the top of the incline?


600j

1000j

4800j

800j

Respuesta :

Explanation:

We have,

According to attached figure, the height of the inclined plane is 60 m and force acting on the block is 10 N. It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :

W = mgh

or

[tex]W=F\times h\\\\W=10\times 60\\\\W=600\ J[/tex]

Hence, the correct option is (A) "600 J".

Ver imagen PhantomWisdom

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